Scientific American Supplement, No. 520, December 19, 1885 by Various
page 64 of 123 (52%)
page 64 of 123 (52%)
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k (t'-t)dS dR = ( -- ) ----------. (2) 60 33,000 To the same scale as the power gains, upon each ordinate, set off the appropriate power loss, as calculated by this equation (2). There will result the curve r, r, r, which determines the power which at any point in the diagram is to be regarded as a loss, to be carried to the debit side of the account. This curve of losses intersects the curve of gains at a point (it is evident) where each equals the other. Therefore this is the point at which expansion should cease, and this absolute pressure is the economic terminal pressure, which determines the number of expansions profitable under the given conditions. In the foregoing example are taken k = 0.3070554, t' = 331.169, t = 60, while the back pressure was taken at 7 pounds. By way of further illustration, first let the back pressure be changed from 7 to 5. By equation 1 there will result a new curve of gains, W, W, W, a portion only being plotted. Second, let t' = 331.169 as before. t = 150 instead of 60. k = 0.2507097 instead of 0.3070554. |
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