[TeX: $W = \frac{4 \times 1250 bd^2}{L}$]

or

5000 bd²
W = --------.
L


[TeX: $W = \frac{5000 bd^2}{L}$]

But, to reduce the load to the proper working strain, we must divide
this equivalent by 4, the factor of safety, and we shall have

5000 bd²
W = --------.
4L

[TeX: $W = \frac{5000 bd^2}{4 L}$]

Let us apply the formula--

Case I. Given a span of 14 feet,
a breadth of 8 inches,
a depth of 14 inches.

Required the safe load.

5000 bd²