Instructions on Modern American Bridge Building by G. B. N. (George Bates Nichols) Tower
page 39 of 57 (68%)
page 39 of 57 (68%)
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[TeX: $\frac{300000 \times 100}{96} = 3333333$]
The dimensions of the chord and splicing would be found in the same manner as for a Howe Truss. =Suspension Rods.= Fig. 1, Pl. III., represents an elevation of a Pratt Bridge. Now, it is evident that the first sets of rods must support the weight of the whole bridge and its load, which we have found to be 300000 lbs. Each truss will have to sustain 150,000 lbs., and each end set of rods 75,000 lbs. Now, if there are two rods in each set,--each rod will have to bear a strain of 37500 lbs., and this will have an increase due to its inclination, so that the strain on it must be found by the following proportion: Height : diagonal :: W : W' or 12 : 15.8 :: 37500 : 49375 lbs. Referring to the Table for bolts, we find that 2-1/8 gives a strength a little in excess, and will be the proper size. The next set of rods bear the weight of the whole load, less that due to the two end panels, and so on. Fig. 2, Pl. III, shows the manner of applying the rods. The bevel block should be so fitted to the chord that it will not have a crushing action. =Counters.= Top and bottom chords are always used in this bridge, and consequently the counter rods have only to sustain the movable load on one panel. The weight of the moving load cannot be more than 2000 lbs. |
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