Piano Tuning - A Simple and Accurate Method for Amateurs by J. Cree (Jerry Cree) Fischer
page 107 of 160 (66%)
page 107 of 160 (66%)
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Now bear in mind, this last fraction, 625/1296, represents the segment of the entire string which should sound the tone 3C, an exact octave above middle C. Remember, our law demands an exact half of a string by which to sound its octave. How much does it vary? Divide the denominator (1296) by 2 and place the result over it for a numerator, and this gives 648/1296, which is an exact half. Notice the comparison. 3C obtained from a succession of exact minor thirds, 625/1296 3C obtained from an exact half of the string 648/1296 Now, the former fraction is smaller than the latter; hence, the segment of string which it represents will be shorter than the exact half, and will consequently yield a sharper tone. The denominators being the same, we have only to find the difference between the numerators to tell how much too short the former segment is. This proves the C obtained by the succession of minor thirds to be too short by 23/1296 of the length of the whole string. If, therefore, all octaves are to remain perfect, it is evident that _all minor thirds must be tuned flatter than perfect_ in the system of equal temperament. The ratio, then, of 648 to 625 expresses the excess by which the true octave exceeds four exact minor thirds; consequently, each minor third must be flatter than perfect by one-fourth part of the difference between these fractions. By this means the dissonance is evenly distributed so that it is not noticeable in the various chords, in the major and minor keys, where this interval is almost invariably |
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