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Piano Tuning - A Simple and Accurate Method for Amateurs by J. Cree (Jerry Cree) Fischer
page 107 of 160 (66%)

Now bear in mind, this last fraction, 625/1296, represents the segment
of the entire string which should sound the tone 3C, an exact octave
above middle C. Remember, our law demands an exact half of a string by
which to sound its octave. How much does it vary? Divide the
denominator (1296) by 2 and place the result over it for a numerator,
and this gives 648/1296, which is an exact half. Notice the
comparison.

3C obtained from a succession of exact minor thirds, 625/1296
3C obtained from an exact half of the string 648/1296

Now, the former fraction is smaller than the latter; hence, the
segment of string which it represents will be shorter than the exact
half, and will consequently yield a sharper tone. The denominators
being the same, we have only to find the difference between the
numerators to tell how much too short the former segment is. This
proves the C obtained by the succession of minor thirds to be too
short by 23/1296 of the length of the whole string.

If, therefore, all octaves are to remain perfect, it is evident that
_all minor thirds must be tuned flatter than perfect_ in the system of
equal temperament.

The ratio, then, of 648 to 625 expresses the excess by which the true
octave exceeds four exact minor thirds; consequently, each minor third
must be flatter than perfect by one-fourth part of the difference
between these fractions. By this means the dissonance is evenly
distributed so that it is not noticeable in the various chords, in the
major and minor keys, where this interval is almost invariably
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