Scientific American Supplement, No. 415, December 15, 1883 by Various
page 31 of 126 (24%)
page 31 of 126 (24%)
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right angled triangle, its hypothenuse will equal the greater diameter.
Hence in order to find the distance between the foci, when the length and width of the ellipse are known, these two are squared and the lesser square subtracted from the greater, when the square root of the difference will be the quantity sought. For example, if it be required to describe an ellipse that shall have a length of 5 inches and a width of 3 inches, the distance between the foci will be found as follows: (5 x 5) - (3 x 3) = (4 x 4) or __ 25 - 9 = 16 and \/16 = 4. In the shop this distance may be found experimentally by laying a foot rule on a square so that one end of the former will touch the figure marking the lesser diameter on the latter, and then bringing the figure on the rule that represents the greater diameter to the edge of the square; the figure on the square at this point is the distance sought. Unfortunately they rarely represent whole numbers. We present herewith a table giving the width to the eighth of an inch for several different ovals when the length and distance between foci are given. Length. Distance between foci. Width. Inches. Inches. Inches. 2 1 1¾ 2 1½ 1¼ 2½ 1 2¼ 2½ 1½ 2 |
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