An Introductory Course of Quantitative Chemical Analysis - With Explanatory Notes by Henry P. Talbot
page 75 of 272 (27%)
page 75 of 272 (27%)
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is most easily noted, and the excess of the reagent is most readily
removed. The latter object is accomplished by oxidation to stannic chloride by means of mercuric chloride added in excess, as the mercuric salts have no effect upon ferrous iron or the bichromate. The reactions involved are: 2FeCl_{3} + SnCl_{2} --> 2FeCl_{2} + SnCl_{4} SnCl_{2} + 2HgCl_{2} --> SnCl_{4} + 2HgCl The mercurous chloride is precipitated. It is essential that the solution should be cold and that the stannous chloride should not be present in great excess, otherwise a secondary reaction takes place, resulting in the reduction of the mercurous chloride to metallic mercury: SnCl_{2} + 2HgCl --> SnCl_{4} + 2Hg. The occurrence of this secondary reaction is indicated by the darkening of the precipitate; and, since potassium bichromate oxidizes this mercury slowly, solutions in which it has been precipitated are worthless as iron determinations.] [Note 3: The solution should be allowed to stand about three minutes after the addition of mercuric chloride to permit the complete deposition of mercurous chloride. It should then be titrated without delay to avoid possible reoxidation of the iron by the oxygen of the air.] |
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