measuring down on the arc _c'_ and establishing the point _t_. The
points _p_ and _t_ are then connected, and thus the impulse face of the
entrance pallet _B_ is defined. From the point _t_ is drawn the line
_t t'_, parallel to the line _b s_, thus defining the inner face of the
entrance pallet.


DELINEATING THE EXIT PALLET.

To delineate the exit pallet, sweep the short arc _u u_ (from _g_ as a
center) with the dividers set at five inches, and from the intersection
of this arc with the line _g j'_ set off eight and one-half degrees and
draw the line _g l_. At one degree below this line is drawn the line _g m_.
The space on the arc _f_ between these lines defines the locking
face of the exit pallet. The point where the line _g m_ intersects the
arc _f_ is named the point _x_. From the point _x_ is erected the line
_x w_, perpendicular to the line _g m_. From _x_ as a center, and with
the dividers set at five inches, the short arc _y y_ is swept, and on
this arc are laid off twelve degrees, and the line _x z_ is drawn, which
line defines the locking face of the exit pallet.

Next is taken ten and one-half degrees from the brass degree-scale, and
from the point _d_ on the arc _n_ the space named is laid off, and thus
is established the point _v_; and from _g_ as a center is swept the arc
_v' v'_ through the point _v_. It will be evident on a little thought,
that if the tooth _A'_ impelled the exit pallet to the position shown,
the outer angle of the pallet must extend down to the point _v_, on the
arc _v' v'_; consequently, we define the impulse face of this pallet by
drawing a line from point _x_ to _v_. To define the outer face of the
exit pallet, we draw the line _v e_ parallel to the line _x z_.